4x^2+1600x-1500=0

Solution for 4x^2+1600x-1500=0 equation:

4x^2+1600x-1500=0

a = 4; b = 1600; c = -1500;
Δ = b2-4ac
Δ = 16002-4·4·(-1500)
Δ = 2584000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2584000}=\sqrt{1600*1615}=\sqrt{1600}*\sqrt{1615}=40\sqrt{1615}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1600)-40\sqrt{1615}}{2*4}=\frac{-1600-40\sqrt{1615}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1600)+40\sqrt{1615}}{2*4}=\frac{-1600+40\sqrt{1615}}{8}
$